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<!DOCTYPE html> <meta charset="utf-8"> <link href="/static/next/css/tryit.css?v=2017082407" rel="stylesheet"/> <script src="https://cdn.staticfile.org/jquery/2.2.4/jquery.min.js"></script> <style> .siblings *{ display: block; border: 2px solid lightgrey; color: lightgrey; padding: 5px; margin: 15px; } </style> <script> $(document).ready(function(){ var DOM=document.getElementsByClassName("li.stop"); $("li.start").prevUntil(DOM,".1").css({"color":"red","border":"2px solid red"}); }); </script> <div style="width:500px;" class="siblings"> <ul>ul (父节点) <li class="stop">li (类名为"stop"的兄弟节点)</li> <li class="1">li (类名为"start"的li节点的上一个兄弟节点)</li> <li>li (类名为"start"的li节点的上一个兄弟节点)</li> <li class="1">li (类名为"start"的li节点的上一个兄弟节点)</li> <li class="start">li (类名为"start"的li节点)</li> <li>li (兄弟节点)</li> <li>li (兄弟节点)</li> </ul> </div> <p>在这个例子中,我们缩小搜索结果只返回在类名为“star”和“stop”的li元素之间类名为“1”的上一个兄弟元素</p> <footer>简单教程，简单编程<br/>Copyright © 简单教程 www.twle.cn</footer>
运行结果：