C 范例 - 计算 int, float, double 等字节大小
使用 sizeof
操作符计算int, float, double 和 char 四种变量字节大小。
sizeof 是 C 语言的一种单目操作符,如C语言的其他操作符++、--等,它并不是函数。
sizeof 操作符以字节形式给出了其操作数的存储大小。
/** * file: main.c * author: 简单教程(www.twle.cn) */ #include <stdio.h> int main() { int integerType; float floatType; double doubleType; char charType; // sizeof 操作符用于计算变量的字节大小 printf("Size of int: %ld bytes\n",sizeof(integerType)); printf("Size of float: %ld bytes\n",sizeof(floatType)); printf("Size of double: %ld bytes\n",sizeof(doubleType)); printf("Size of char: %ld byte\n",sizeof(charType)); return 0; }
编译运行范例,输出结果如下
$ gcc main.c && ./a.out Size of int: 4 bytes Size of float: 4 bytes Size of double: 8 bytes Size of char: 1 byte
计算 long long, long double 字节大小
/** * file: main.c * author: 简单教程(www.twle.cn) */ #include <stdio.h> int main() { int a; long b; long long c; double e; long double f; printf("Size of int = %ld bytes \n", sizeof(a)); printf("Size of long = %ld bytes\n", sizeof(b)); printf("Size of long long = %ld bytes\n", sizeof(c)); printf("Size of double = %ld bytes\n", sizeof(e)); printf("Size of long double = %ld bytes\n", sizeof(f)); return 0; }
编译运行范例,输出结果如下
$ gcc main.c && ./a.out Size of int = 4 bytes Size of long = 8 bytes Size of long long = 8 bytes Size of double = 8 bytes Size of long double = 16 bytes