C 语言范例 - 计算两个时间段的差值
计算两个时间段的差值
/** * file: main.c * author: 简单教程(www.twle.cn) */ #include <stdio.h> struct TIME { int seconds; int minutes; int hours; }; void diff_of_times(struct TIME t1, struct TIME t2, struct TIME *diff); int main() { struct TIME startTime, stopTime, diff; printf("输入开始时间: \n"); printf("输入小时、分钟、秒:"); scanf("%d %d %d", &startTime.hours, &startTime.minutes, &startTime.seconds); printf("输入停止时间: \n"); printf("输入小时、分钟、秒: "); scanf("%d %d %d", &stopTime.hours, &stopTime.minutes, &stopTime.seconds); // 计算差值 diff_of_times(startTime, stopTime, &diff); printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds); printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds); printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds); return 0; } void diff_of_times(struct TIME start, struct TIME stop, struct TIME *diff) { if(stop.seconds > start.seconds){ --start.minutes; start.seconds += 60; } diff->seconds = start.seconds - stop.seconds; if(stop.minutes > start.minutes){ --start.hours; start.minutes += 60; } diff->minutes = start.minutes - stop.minutes; diff->hours = start.hours - stop.hours; }
编译运行范例,输出结果如下
$ gcc main.c && ./a.out 输入开始时间: 输入小时、分钟、秒:22 22 22 输入停止时间: 输入小时、分钟、秒: 8 8 8 差值: 22:22:22 - 8:8:8 = 14:14:14